[tex] - ( \frac{x + 3}{ - x - 1 } -\frac { 1} { - 2} ) - \frac {2}{1} = [/tex]
mohon bantuannya
[tex]- ( \frac{x + 3}{ - x - 1 } -\frac { 1} { - 2} ) - \frac {2}{1} \\ \\ = - ( \frac{ - 2(x + 3) - 1( - x - 1)}{( - x - 1) - 2}) - \frac{2}{1} \\ \\ = - ( \frac{ - 2x - 6 + x + 1}{2x + 2}) - \frac{2}{1} \\ \\ = - ( \frac{ - x - 5}{2x + 2}) - \frac{2}{1} \\ \\ = \frac{x + 5}{ - 2x - 2} - \frac{2}{1} \\ \\ = \frac{1(x + 5) - 2( - 2x - 2)}{1( - 2x - 2)} \\ \\ = \frac{x + 5 + 4x + 4}{ - 2x - 2} \\ \\ = \frac{5x + 9}{ - 2x - 2} \\ \\ = \frac{5x + 9}{ \frac{1}{(2x + 2)} } \\ \\ = 5x + 9 \times 2x + 2 \\ \\ = 10x + 18[/tex]
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